I was studying the applications of the Schröedinger wave function in the Bohr's atom.
For what I understood, the $\psi$ should only depend on r and not on $\theta$ and $\phi$. Does that mean that $\psi(r, \theta, \phi)=R(r)$?
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In general the wavefunction depends on all the coordinates. However, there are special states called $s$ states, without any angular momentum, where it depends only on $r$.
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$\begingroup$ And there is a symmetry in the $1/r^2$ potential that makes that other values of the angular momentum quantum number have the same energy. $\endgroup$– user137289Commented Nov 29, 2019 at 0:25