# Faraday's Law and Electromagnetic Induction

Faraday's Law of electromagnetic induction states that the rate of change of magnetic flux linkage is proportional to the $$\mathcal{emf}$$ induced. For a conductor, the formula goes

$$\mathcal{emf}=N\frac{\Delta\Phi}{\Delta t}$$

Where $$N$$ is the number of coils within the wire, $$\Phi$$ is the magnetic flux linkage, and $$t$$ is time.

However, what I do not understand is how does $$N$$ become a variable within the formula. The principle underlying electromagnetic induction is the rate of change of flux linkage, but $$N$$ is independent of area, though related to $$B$$, magnetic flux density.

Through the relationship

$$\Phi=NBA$$

It becomes intuitive if the $$N$$ refers to the number of coils of the solenoid $$X$$ which provides the magnetic field and $$B$$ is the magnetic flux density provided by a single unit coil of solenoid $$X$$, but I do not quite understand how to perceive the formula if the circumstances are reversed,

Where $$N$$ becomes the number of coils of a solenoid $$Y$$ which will have an $$\mathcal{emf}$$ induced, while $$B$$ refers the magnetic flux density of solenoid $$X$$ which induces the $$\mathcal{emf}.$$

I wish for clarification of the variable $$N$$ within these types of phenomenon, because I cannot see an intuitive way to link the concept of magnetic flux linkage and induced $$\mathcal{emf}$$ with it.

• Faraday's law is that the emf is equal to $-d\Phi_B/dt$, with $\Phi_B$ being the magnetic flux through some 2D sheet. In the specific case where the magnetic field passes through a coil of $N$ loops, the overall area the field passes through is just $N$ times the area of each loop, so one gets emf = $-N d\Phi_{loop}/dt$. The $N$ is there to make the calculation easier, by considering the area and flux through one loop, multiplying by $N$ to get the total area/flux. – PhysicsTeacher Nov 24 '19 at 19:53

Imagine a situation like this (sorry for a bad figure). I have tried to make a coil of wire with N turns in total (all the turns are connected but if I would have done that then image would have become messy) and the red arrows represent the magnetic field lines. Since each loop has same area so magnetic flux will be the same through all of the loops (I'm considering magnetic field B to be uniform inside the coil) and any change in magnetic field B will cause the same change in magnetic flux in all the loops. So, emf developed in each loop is given by Faraday's Law as $$\mathcal{emf} = -\frac{d\phi}{dt}~~~~~~~(1)$$ Now, since we have $$N$$ loops and in each loop the emf is $$-\frac{d\phi}{dt}$$ therefore total emf from A to B is the sum of these emf and hence $$\mathcal{emf_{A ~to~ B} } = -N \frac{d\phi}{dt}$$ Your intuitive problem was that why does the emf depends on number of turns when it has been found experimentally that emf depends only on magnetic flux which in it's turn depends on the area of the loop, well as you have seen from mathematics done above, the emf is caused in each loop according to Faraday's Law but due to connectivity we got a total sum of all emf from one end to the other.