Hawking radiation in an eternal black hole background This is a question about Hawking radiation in a fixed Schwarzschild background. The radiation does not back react on the metric and the black hole can not grow or evaporate.
Now I've seen Hawking radiation derived using either a Bogoliubov transformation or by using path integral arguments, so I understand that the vacuum state for a quantum field in the Schwarzchild background will be in a thermal equilibrium state in terms of the Hamiltonian that generates time translations in the Schwarzschild coordinate time.
My question is how is this interpreted as radiation coming from the black hole? This is an equilibrium state that does not change with time and unless I'm missing something there are as many particles moving radially in to the black hole as out from it.
Where are the particles from infinity coming from? Does an observer far from the black hole observe as much radiation as an observer near it?
Basically my confusion is coming from the fact that the state is expressed as a thermal distribution of modes without obvious (to me) spatial dependence. So I'm wondering how people jumped to the interpretation that all of the radiation in this vacuum state is coming from the black hole.
There is a very similar question here: Eternal black holes and Hawking radiation. But I am aware of the fact that this is a fixed background metric, and this still doesn't answer my questions of how the radiation is interpreted.
 A: The local picture usually comes from looking at $\langle T_{\mu\nu} \rangle _{ren}$, the renormalized semiclassical energy-momentum tensor. For a BH formed by stellar collapse it shows a flux of negative energy into the horizon and a thermal Hawking flux out to infinity, as calculated for example by Davies, Fulling, and Unruh 1976.
For a purely Schwarzchild eternal BH with no collapse, this local picture will depend on the boundary conditions (i.e. on the choice of quantum state), and there is no obvious way to say which represents the "real" physics. After all, no actual objects with that geometry are known to exist. States like the one you mention where an equal number of particles fall in as go out are not evaporating, they are in equilibrium. EDIT: The energy-momentum for various states in this background was discussed e.g. by Candelas 1980.
And watch out for treating the Bogoliubov particle calculations as locally meaningful, which can be misleading as shown e.g. by Padmanabhan and Singh 1987.
