0
$\begingroup$

I can't work out c) for the following question, and I'd just like some help clarifying why my solution is wrong. Part a) and b) are fine.

A car rounds a bend on a road that follows the arc of a circle with radius 25.6 metres. The car has a mass of 885 kg and the force of kinetic friction between the tyres and the road is 9420 N

a) At what maximum speed should the car be moving so as to stay on the road?

b) Using Physics principles and your answer from above, quantitatively explain why motorists are advised to drive at slower speeds in wet weather.

c) If the bend in a) was banked at 8 degrees to the horizontal, show quantitatively how this increases the maximum speed that allows the car to remain on the road.

For a):

F(centripetal) = m*v^2 / r
           v^2 = 25.6*9420 / 885 = 272.4...
           v   = 16.5m/s

For b):

In wet weather, friction is decreased. As v = sqrt(v*F(c) / m), v will decrease if friction decreases. Hence, motorists must drive slower in wet weather to avoid slipping off the road.

For c):

See this image for a diagram of an inclined plane.

To find the coefficient of friction, we can say that u = static friction / normal force. In this case, static friction = mgsinθ and normal force = mgcosθ.

Hence, u = tan(8) = 0.1405...

By equating formulas for centripetal force:

m*v^2 / r = u*m*g
v^2 = 35.3
v = 5.94 m/s

Which is less than 16.5 m/s. I'm not sure where I went wrong, any help would be appreciated. Thanks.

$\endgroup$
0
$\begingroup$

HINT:

The part where you equated friction and normal forces with components of gravity along the incline and perpendicular to it is wrong as the body will be accelerating in those directions , namely components of centripetal acceleration.

Also, you can't find coefficient of static friction with the date given but you have to only give a qualitative reasoning.

See, if you can do it now.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.