So for two quantum systems a and b in a joint state
$$\Psi = \lvert \psi_a \rangle\lvert \psi_b \rangle \tag{1}$$
With basis states $\{\lvert \phi_k \rangle\}$ for system a and $\{\lvert v_j \rangle\}$ for system b, and operator A acting on the Hilbert space of a with the spectral decomposition
$$ A = \lambda_1\lvert \phi_1 \rangle \langle \phi_1 \rvert + \lambda_2\sum_{n=2}^N \lvert \phi_n \rangle \langle \phi_n \rvert \ \tag{2}$$
I am trying to understand how I can write an expression for the projector acting on the total Hilbert space and which is associated to the measurement outcome $\lambda_2$ so I can then calculate the probability of obtaining $\lambda_2$ in a measurement of A on the state $\Psi$.
My understanding is that only the second term of equation 2 is relevant for this measurement as it contains the coefficient $\lambda_2$. Operator A only acts on the Hilbert space of a, so am I correct in writing that the projector acting on the total Hilbert space is the following? $$ (\lambda_2\sum_{n=2}^N \lvert \phi_n \rangle \langle \phi_n \rvert) \otimes I \tag{3} $$
And if the probability of measuring $\lambda_2$ is the following (because there are multiple projectors corresponding to the measurement $\lambda_2$) $$ \langle \Psi \rvert \ \sum_{n=2}^N \lvert \phi_n \rangle \langle \phi_n \rvert \Psi \rangle \tag{4} $$
If anyone could point out if I'm correct or wrong with my answers/reasoning and why, it would be much appreciated. I also would like to know if I can write my expressions in a simpler way. Finally, I would like to ask that since only the Hilbert space of a is concerned in this measurement, does that mean the basis states for system b is completely irrelevant even if I change them? Thank you.