1
$\begingroup$

A hole is the lack of an electron.

Thus, if we consider for example a N doped semiconductor. The so-called "majority charge carriers" are the electrons. But whenever there is a mobile electron that moves from a site to another site, the former site will have a hole, thus I don't see why there would not be exactly the same number of holes as the number of electrons.

Thus, I don't catch why the electrons would be really "majoritary", for example in a N semiconductor.

$\endgroup$
  • 1
    $\begingroup$ I'm not sure that this is the explanation. Let's see other comments. $\endgroup$ – Mathieu Krisztian Nov 3 '19 at 9:42
  • 1
    $\begingroup$ I am with you Mathieu. I won't buy that cheap argument, because electrons aren't particles but quasiparticles in solids, too. $\endgroup$ – AccidentalBismuthTransform Nov 3 '19 at 12:21
  • 2
    $\begingroup$ If a semiconductor is doped n-type (for example), then there are (mobile) electrons in the conduction band even if the valence band is full (no holes) so I don't understand your argument. $\endgroup$ – Alfred Centauri Nov 3 '19 at 14:00
  • $\begingroup$ Thank you Alfred. I believe that your explanation is the best one. Thank you. $\endgroup$ – Mathieu Krisztian Nov 3 '19 at 15:51
  • 1
    $\begingroup$ @Alfred thank you. I was not aware of that. $\endgroup$ – Mathieu Krisztian Nov 6 '19 at 17:55
2
$\begingroup$

Your argument only holds for undoped (intrinsic) semiconductors. Doping introduces one type of carriers and creates a strong asymmetry in the concentration of both carrier types.

| cite | improve this answer | |
$\endgroup$
  • $\begingroup$ All right thank you. Actually I feel that the best explanation was the one from Alfred Centauri. $\endgroup$ – Mathieu Krisztian Nov 3 '19 at 15:51
  • 1
    $\begingroup$ Really? They are they same except that I pointed out your error in more detail. $\endgroup$ – my2cts Nov 3 '19 at 15:56
  • $\begingroup$ ok, actually, Alfred gives an extra information, which is useful. Maybe you may merge his information in your answer, for people that may ask themselves the same question. Thank you. $\endgroup$ – Mathieu Krisztian Nov 3 '19 at 15:57
  • $\begingroup$ Which extra information in which answer ? I only see a comment. $\endgroup$ – my2cts Nov 3 '19 at 16:00
  • 1
    $\begingroup$ I cannot follow your reasoning. You should read up on semiconductors. $\endgroup$ – my2cts Nov 3 '19 at 16:51

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.