So I've been doing a lot of research on spinning black holes and fumbled upon the concept of a "naked singularity" where a gravitational singularity exists without an event horizon. Ignoring the physics-breaking problems and questions it raises, how would this behave in comparison to a spinning black hole?

For example(s): Would it have an accretion disk? Would matter still get spaghettify if it got too close? Could you get in and out to observe it while once you pass the even horizon of a reg black hole, you can't get out?

tl;dr, would it act the same as a regular spinning black hole?

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    $\begingroup$ It depends a lot on the type of naked singularity - different GR solutions have very different singularities. If it has curvature that increases as the singularity is approached one gets gravitation-like effects, but there are AFAIK crease- and point-like singularities with no increasing curvature too. $\endgroup$ Nov 3, 2019 at 10:06
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    $\begingroup$ If the singularity is naked, then predictability is lost and you cannot say anything. So, you can have an accretion disk or you could have a green slime monster as the standard example goes. $\endgroup$
    – MBN
    Nov 4, 2019 at 11:34
  • $\begingroup$ related: physics.stackexchange.com/questions/455726/… $\endgroup$
    – user4552
    Nov 4, 2019 at 13:51
  • $\begingroup$ You could get in and out to observe a naked singularity. It has no event horizon by definition, which means it's necessarily true that you can observe it $\endgroup$
    – Jim
    Nov 4, 2019 at 14:26
  • $\begingroup$ @safesphere : The big bang and crunch singularities are not naked. At least that is the standard terminology. $\endgroup$
    – MBN
    Nov 5, 2019 at 10:29

1 Answer 1


Assuming you are asking about the type of naked singularity you get if consider the Kerr solution with spin greater than 1.

In some respects this solution behaves just like a Kerr black hole. For example, there still is an innermost stable circular orbit. Hence it could still have an accretion disk with an inner edge. Tidal effects would also still diverge as you approach the singularity leading to "spaghettification".

However, there also some crucial differences: For example there is no photon sphere, meaning the object would look very different when view by the event horizon telescope. Also, most matter falling toward the singularity will miss the singularity and be flung back out.

(And of course, there is the singularity itself, for which we have no clue how it would interact with other objects or fields.)

  • $\begingroup$ not saying I don't believe you LOL; you're def more knowledgeable than I am and with the research I've done, I agree. Though I'm confused on the "most matter falling toward the singularity will miss the singularity an be flung back out." Could you explain how/why that works? $\endgroup$
    – buiud
    Nov 7, 2019 at 3:36

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