0
$\begingroup$

Imagine a $1$ meter airtight cube at room temperature with a large bucket of water in it.

What would would happen if you removed all the atmosphere?

I know the water would evaporate, but eventually wouldn't the evaporated water raise the air pressure so the water no longer evaporates?

Since the water is at room temperature I would think the water in the air would condensate, but the water condensing would also lower the air pressure.

How would this actually work?

$\endgroup$

1 Answer 1

1
$\begingroup$

Actually a dynamic equilibrium will be attained where the rate of evaporation will be equal to the rate of condensation.

It is to be noted that the rate of evaporation remains nearly constant if the water is kept at the same temperature and the surface area is the same. However the rate of condensation will increase and as I've said before, a dynamic equilibrium will be reached.

The vapor pressure of water vapor will eventually increase and at equilibrium it will be called the "saturated vapor pressure".

enter image description here

$\endgroup$
3
  • $\begingroup$ So, the water would just eternally evaporate, with the water supply being constantly replenished by the condensate? $\endgroup$
    – Bitsplease
    Oct 25, 2019 at 4:40
  • $\begingroup$ @AustinPhilp If you mean the water in the bucket...then you're right...Remember the necessary conditions have to be maintained. $\endgroup$ Oct 25, 2019 at 4:45
  • $\begingroup$ Won't the rate of evaporation decrease because of I)decreased temp of bucket water from evap. II)increased pressure III)more humidity in the container $\endgroup$
    – lineage
    Oct 25, 2019 at 7:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.