ZAMO's trajectory near a Kerr Black Hole? sorry for the "generic" question, just that the last month I have been studying GR from 0 and having problems understanding some of the concepts. Anyways, to the question I wanted to ask:
From my understandings, ZAMO (Zero Angular Momentum Observer) Co-Rotates with the same Angular speed around the black hole, right?
Does this means that he HAS Angular momentum for an Euclidean/Lorentzian Observer far far away from the Black hole?
ZAMO holds the equation $r=C_0$, but $\phi \neq C_1$ right?
 A: ZAMOs are basically the observers having zero angular momentum at infinity. So what does this mean?
In General Relativity (GR), angular momentum of a test particle is defined as 
$$l=g_{t\phi}\frac{dt}{d\tau}+g_{\phi\phi}\frac{d\phi}{d\tau}$$
where $t$ is the coordinate time and $\tau$ is the proper time. Now far from a compact object (i.e. at infinity), we have $g_{t\phi}\rightarrow0$ and $g_{\phi\phi}\rightarrow1$. So at large distances, we have 
$$l=\frac{d\phi}{d\tau}$$
This is exactly the definition of angular momentum defined in the proper frame. Now when we say that the angular momentum is zero, we mean that $l=0$.
Q. What would happen when the particle approach a compact object (e.g., Kerr black hole)?
A. Put $l=0$ in the first equation to obtain $$\frac{d\phi}{dt}=\frac{d\phi/d\tau}{dt/d\tau}=\frac{\dot{\phi}}{\dot{t}}=-\frac{g_{t\phi}}{g_{\phi\phi}}$$
Recall that this is nothing but the frame dragging angular velocity which one can obtain from the Kerr metric, so that we obtain
$$\omega(r,\theta)=-\frac{g_{t\phi}}{g_{\phi\phi}}$$
MORAL:
ZAMOs are the observers who have zero angular momentum ($l=0$) in their proper frame at large distances. But as they approach any compact object, frame dragging pulls it along with the geometry so that they attain the angular velocity $\omega(r,\theta)$, the frame dragging angular velocity.
A: In general questions like

Does this means that he HAS Angular momentum for an Euclidean/Lorentzian Observer far far away from the Black hole?

are meaningless in general relativity. In general, a distant observer would have no meaningful definition of the angular momentum of an object at a different location.
More to the point. In the case of a Kerr black hole a ZAMO is defined to be an observer with zero angular momentum defined as the conserved quantity related to the rotational symmetry of the Kerr spacetime.
As it happens, because Kerr is asymptotically flat, it also has a notion of the total angular momentum of the spacetime, in the form of the so-called ADM angular momentum. One can prove (but this is far from trivial) that a ZAMO will not contribute to the ADM angular momentum.
