We know that $C=q/U$. We know that the voltage is the potential difference between the plates. If we have a capacitor on which we apply voltage, the one plate charges up and induces the other one with an equal and opposite charge. If we connect one of the plates to ground, will the voltage change ? if so why? If not, why?
By grounding, we give one of the plates an infinite sink/well of charge (meaning by grounding we either let the positively charged plate get it's missing charge, or the excess electrons on the negative plate to go into the ground. Therefore, we change the potential on one of the plates. So the voltage (the potential difference) drops. Am I missing something? Is it right?