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I saw this example at griffiths. It’s a basic question about gauss’s law but I saw the electric field being treated as a constant and thus, it got outside of the integral. I couldn’t quite understand this.

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closed as unclear what you're asking by Kyle Kanos, Aaron Stevens, Jon Custer, stafusa, Daniel Griscom Oct 24 at 2:40

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  • $\begingroup$ Is there spherical symmetry in the distribution of charge? To use Gauss's Law efficiently, you should identify symmetries in the problem. $\endgroup$ – Bill N Oct 17 at 19:20
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Assuming the charge carriers are not prevented from moving in the material of the sphere (e.g. they are mobile charge carriers in a conducting solid sphere), the charges will distribute themselves uniformly so that at equilibrium the electric field is zero anywhere within the sphere. In other words, a uniform distribution insures an electrostatic condition in the conducting material.

Hope this helps

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  • $\begingroup$ I see I get it now. Sorry for such a simple question $\endgroup$ – user244918 Oct 16 at 8:21
  • $\begingroup$ @user244918 no problem. Glad it helped $\endgroup$ – Bob D Oct 16 at 8:23
  • $\begingroup$ @user244918 Why don't you accept Bob D's answer, if you are satisfied ? $\endgroup$ – Alfred Oct 16 at 8:45
  • $\begingroup$ I’m new to this site, forgot to accept, sorry. $\endgroup$ – user244918 Oct 16 at 10:11
  • $\begingroup$ @user244918 no problem. It happens a lot with new contributors $\endgroup$ – Bob D Oct 16 at 10:47

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