I think i get the concept of the Bernoulli equation pretty well, but I have a hard time understanding the Pitot tube.
We have the Bernoulli equation for the Pitot tube: $P_1=P_2+(\rho V_2^2)/2$, where $P_1$ is pressure in the stagnation point $1$ and $P_2$ is the pressure in the point $2$.
Now, let's assume that the aircraft is not moving. Let's blow a stream of air over the point $2$, like in the theoretical example, but we don't blow any air towards point $1$, like we did in the theoretical example. The velocity at point $1$ will still be zero, and the Bernoulli equation will have the same form: $P_1=P_2+(\rho V_2^2)/2$, Which should not be correct.
Where is the mistake in my reasoning?