"Pascal's Principle" hydraulic lift is (F1) the equilibrium to (F2) or alike to the "See-Saw Principle" is (F1) lifting (F2) past equalibrium?  I've been trying to understand "pascals principle" and thus far have learned a lot thanks to this forum. I have a few more questions regarding the topic so along the way please correct me if I'm wrong.

I've found this data using a few equations and I'd like to know if there are any differences between these two drawings above? Also the relevant question mentioned in the title. Considering both photo's the fluid volumes, pipe bores, & loads are all of the same dimensions as the hydraulic lift shapes are the only differences.

Using formulas f2 = a2 / a1 and the mechanical advantage ma = f2 / f1 I've found my data as of:

MA = 7

F1 = 507 N or 114 lb Pipe/piston diameter = 3"

F2 = 3,549 N or 798 lb Pipe/piston diameter = 8"

Question: With this data is (f1) required to lift (f2)? Or it required to just be at equilibrium & balance each other out?

If the answer is that it is required to lift (f2) then how do I find out what weight is required to be at equilibrium of the two weights?

Now If the answer is that (f1) is required to be at equilibrium with (f2) is it reasonable to assume that if I added only 1 extra lb to (f1), alike to the "See-Saw Principle" (f2) would then be lifted past equilibrium?