Hamilton-Jacobi Equation: Why does any $F(q,Q,0)=f(q,Q)$ lead to a solution? I) Given the Hamilton-Jacobi equation,$$\frac{\partial F(q,Q,t)}{\partial t}+H\left(q,\frac{\partial F(q,Q,t)}{\partial q},t\right)=0 $$
it is stated that any function $$F(q,Q,t=0)=f(q,Q)\tag{22}$$ would generate a solution to the problem. How does that work?
My question arose after reading the document The Hamilton-Jacobi equation 
on page 4, equation 22 — this might help to understand my question.
I have little knowledge of PDE's, so I don't know if this is some general property of PDE's or if there is some other reason for it. 
Is the argument that I can for example numerically integrate the function from this point using the HJ equation to obtain $F(q,Q,t)$ at all other times?
II) I tried to solve the free particle and realised there are some points that are unclear. Given is
$$
H=\frac{p^2}{2m}.
$$
Let 
$$
F(q,Q,t)=W(q,Q)-Qt
$$
and $\frac{\partial F}{\partial q}=p$ and $\frac{\partial F}{\partial Q}=P$. The Hamilton-Jacobi equation is 
$$
H(q,\frac{\partial F}{\partial q},t) + \frac{\partial F}{\partial t} = 0.
$$
This reduces to 
$$
\frac{1}{2m}\left( \frac{\partial W}{\partial q} \right)^2 = Q.
$$
Solving for $W(q,Q)$ by integration over $\int^q_{q_0}dq'$ after rearrangement yields
$$W(q,Q) = \sqrt{2mQ}(q-q_0) + W(q_0, Q).
$$
Now we can write down $F$:
$$
F(q,Q,t)=\sqrt{2mQ}(q-q_0) + W(q_0, Q) - Qt.
$$
Is this not the general solution for the principal function? Is there still some sort of constant or function which I could add or remove from this solution?
 A: I) We can rewrite the HJE
$$\frac{\partial F(q,Q,t)}{\partial t}~=~-H\left(q,\frac{\partial F(q,Q,t)}{\partial q},t\right)$$
with a type 1 generating function $F(q,Q,t)$ into a fixed-point integral equation  $$F(q,Q,t_f)~=~F(q,Q,t_i)-\int_{t_i}^{t_f}\! dt~H(q, \frac{\partial F(q,Q,t)}{\partial q},  t).$$ Given an arbitrary initial profile $$F(q,Q,t_i)~=~f(q,Q)\tag{22}$$ we can in principle find a unique local solution $F(q,Q,t)$  to the HJE, cf. the general mathematical theory for 1st-order non-linear PDEs [2,3].
II) OP considers a free 1D particle, and lists a complete solution of type 1. Similarly, a complete solution to Hamilton's principal function (which is a type 2 generating function) is 
$$S(x,t; \alpha_1, \alpha_2)~=~\alpha_1 x - \frac{\alpha_1^2}{2m}t +\alpha_2. $$  Note however that a complete solution to a PDE is not a general solution [4,5], despite its name! 
References:


*

*S. Mathur, Hamilton-Jacobi equation; p. 4 eq. (22).

*R.L. Bryant, S. S. Chern, R.B. Gardner, H.L. Goldschmidt & P.A. Griffiths, Exterior Differential Systems, 2011; p. 30-35.

*Y. Choquet-Bruhat, C. DeWitt-Morette, Cécile de Witt & M. Dillard-Bleick, Analysis, Manifolds and Physics, Part 1: Basics, 1982; p. 242-258.

*H. Goldstein, Classical Mechanics; Section 10.1 first footnote.

*L.D. Landau & E.M. Lifshitz, Mechanics, vol. 1 (1976); $\S$47 footnote on p. 148.
