1
$\begingroup$

Attached is the graph of photoelectric current vs Anode potential as given in my book for same intensity and different frequencies of incident light for the same metal(hence same work function).

In my opinion this graph isn't the graph for the conditions as mentioned rather, it should be for light with same number of photons incident per unit time per unit area(n), with different frequencies.

$I=nh \nu$, where I is the intensity. As $\nu$ is different, $I$ is also different.

In my opinion, the graph for photoelectric current vs Anode potential for same intensity and different frequencies of incident light for the same metal should be as attached in the free hand drawn diagram as drawn by me(I couldn't find any reference regarding the diagram I got).

Could someone please explain whether my book or I or neither is correct? All my other reference books also seem to suggest the same as given in my book.

P.S. I found few other similar questions asked here before but none of which could answer my query.

Graph from my book graph according to me

Improve this question
$\endgroup$
1
$\begingroup$

Yes, you are right. What you drew can be confirmed from here: Stopping Potential vs Frequency

Improve this answer
$\endgroup$
  • $\begingroup$ Oh ok thank you $\endgroup$ – user600016 Sep 22 '19 at 16:12
  • $\begingroup$ I am still not entirely convinced. There isn't much explanation or details regarding the conditions mentioned. Further, at the bottom of the page, the same thing as mentioned in my book is mentioned. To add to that, the video given in the link also says the same thing at around 14mins $\endgroup$ – user600016 Sep 22 '19 at 16:24

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.