He says there's a low chance he might teleport Mars. Correct me if I'm wrong but this is a gross misunderstanding. If uncertainty of position is high, uncertainty of energy is low, and you would see a faint image of him on Mars in this scenario because energy/momentum would be low due to the high location uncertainty.
Yeah, Kaku is not a practicing physicist, don't take his words literally.
This is a pretty mild flub of his, you can look him up on quora for more. The equation
Says that if we know momentum fairly precisely, like measuring it on Earth, then the location will be uncertain. However, it will be uncertain relative to where we measured it, so if we measured on Earth (for example) $\Delta x$ would be larger to reach Mars and $\Delta p$ would be smaller. In other words, we need to observe Kaku with a high energy photon that sends him to Mars and in order to re-measure him there will be a delay between the measurement and the second measurement because the photon has to reach his new (unknown) location.
So no, you won't teleport to Mars in a meaningful sense.