1
$\begingroup$

Discussion on the drude theory of metal usually begin with the case of zero magnetic field so that the force acting on the electrons is just the one from the electric field. But then, this electric field is related to a charge current density. How is it possible to have a current but there is no magnetic field?

$\endgroup$
  • $\begingroup$ Drude theory does not state that there is or is not a magnetic field. That is the domain of Maxwell's equations. $\endgroup$ – my2cts Aug 20 at 18:43
  • $\begingroup$ Following paper might be interesting: arxiv.org/pdf/1602.03069.pdf $\endgroup$ – Simon Aug 26 at 14:57
0
$\begingroup$

The Drude model is very crude, but it results in the current density J being proportional to electric field E, which in turn brings us to the current I being proportional to voltage V (V = RI). So it provides an reasonable explanation for electrical engineering's most important equation.

Once you have J, you can extract I, and calculate the magnetic field as usual (Biot-Savart Law). It's neglected at first, because the model provides useful results regardless, but you can always consider it if need be.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.