Uncertainty Principle allows the appearance of small amounts of energy from nothing, always on the condition that they disappear in a very short time.

Speaking in seconds, how brief should these phenomena be? Among other things, it serves to explain that, even for a very short time, it is possible to violate the energy conservation law.

I would like to know how long it actually takes (in seconds)

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    $\begingroup$ Related: physics.stackexchange.com/questions/53802/… $\endgroup$ – PM 2Ring Aug 13 at 11:02
  • $\begingroup$ @PM2Ring Maybe is related to here, but seems that "time" here can't be translate in seconds as unit measure of time? $\endgroup$ – Aron Aug 13 at 13:05
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    $\begingroup$ Well, strictly speaking, the uncertainty principle does not allow you to violate the energy conservation law. In QM, energy is always conserved. But anyway, the time-energy uncertainty equation is $\Delta E \Delta t \ge \hbar / 2$. If we treat that as an equality and let $\Delta E$ = 1.022 MeV, the rest energy of an electron + positron pair, we get $\Delta t=3.22\times 10^{-22}$ seconds. But please don't take that calculation too seriously. $\endgroup$ – PM 2Ring Aug 13 at 17:02

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