# Confusion when applying Gauss's Law to a charged sphere

We have a charged sphere with charge Q and the charge is uniformly distributed with a charge density ρ. The sphere has a radius R.

If we construct a Gaussian Surface with radius r, with r < R. If we apply Gauss's law here, we would find the electric field at radius r only depends on how much charge is enclosed in this Gaussian Surface. But how can this be conceptually? How can the charge outside of this Gaussian Surface not contribute any electric field to a point on the Gaussian Surface?

I understand that Gauss's law determines the answer, but any conceptual explanation would be much appreciated.