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In a problem which I was doing, I came across an expression for the potential $V$ of a system as follows $$V = k\left(\frac{1}{l - x} + \frac{1}{l + x}\right)\tag{1}\label{1}$$ where $k$ is a constant, $l$ and $x$ are distances and $l \gg x$. Now I went to find an approximate expression $$V = k\left(\frac{(l + x) + (l - x)}{l^2 - x^2}\right)$$ and reasoning that since $l \gg x$, $l^2 - x^2 \approx l^2$ and thus $$V \approx \frac{2k}{l} \tag{2}\label{2}$$ but this turns out to be wrong as the potential is expected to for an harmonic oscillator and thus propotional to $x^2$. The right way to approximate is \begin{align} V & = \frac{k}{l}\left(\frac{1}{1 - x / l} + \frac{1}{1 + x / l}\right) \\ & \approx \frac{k}{l}\left(\left(1 + \frac{x}{l} + \frac{x^2}{l^2}\right) + \left(1 - \frac{x}{l} + \frac{x^2}{l^2}\right)\right) \\ & \approx \frac{k}{l}\left(2 + \frac{2x^2}{l^2}\right) \end{align}

Ignoring the constant $2$ as I'm concerned about the differences in the potential, I get $$ V \approx \frac{2kx^2}{l^3} \label{3}\tag{3}$$ which is correct.

What mistake did I do in my approximation method?

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    $\begingroup$ There seems to be a small typo, between eqns (2) and (3), when you apply the series expansions in the potential, the second term should have a (-) sign in front of x/l so that the x/l terms cancel out (as shown). $\endgroup$ Aug 4, 2019 at 11:57
  • $\begingroup$ @electronpusher Yep. Thanks for pointing out. $\endgroup$ Aug 4, 2019 at 12:37
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    $\begingroup$ You got $$V \approx \frac{k}{l}\bigg(2+\frac{2x^2}{l^2}\bigg)$$ Now $x^2\lt \lt l^2 \implies x^2<< l^2 \implies\frac{2x^2}{l^2}<<2 \implies \frac{2x^2}{l^2}+2\approx2$ $$\implies V \approx \frac{2k}{l} $$ which is same as the first case. $\endgroup$
    – 19aksh
    Aug 4, 2019 at 13:25

2 Answers 2

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There is nothing wrong with your first approximation. You got the leading term $2k/l$ correct. You just did not expand out far enough in powers of $x/l$ to see the $2k x^2/l^3$ term. If you were to keep going, you would find a term with $x^4/l^5$ and so on. You would need this if you wanted to study how the oscillation frequency varies with amplitude. How far you need to go depends on what effects you are after.

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    $\begingroup$ This is the key issue. You're not just "approximating" in some arbitrary sense, you are approximating with a goal. What approximations are acceptable depends on the goal. $\endgroup$ Aug 5, 2019 at 15:26
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We have $$ x^2 \ll l^2 \implies \frac{2x^2}{l^2} \ll 2 \implies \frac{2x^2}{l^2} + 2 \approx 2 $$ So, $$ V \approx \frac{k}{l} \bigg(2 + \frac{2x^2}{l^2}\bigg) \approx 2\frac{k}{l} $$

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    $\begingroup$ @Nat Thanks for the edit! $\endgroup$
    – 19aksh
    Aug 5, 2019 at 13:11

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