# Reaction forces acting on a ladder against a wall

I've seen some problems that talk about a ladder leaning against a frictionless wall, with a person standing on it. The ladder doesn't move(net force = 0). The problem is, I don't know what directions the reactions forces(that is, the force of the wall on the ladder, and of the floor on the ladder) should have. I've seen it solved like this:

where the force of the wall on the ladder is horizontal, and the force of the floor on the wall is vertical, and also in this way:

where the normal force of the wall is said to have both y and x components.

EDIT: this is a drawing of the forces acting on the ladder. The original image of the situation is

I didn't notice it was leaning against over a corner (and I also wouldn't have thought it would make a difference)

I don't know which interpretation to believe. Is the force of the wall always perpendicular to the wall itself? Or it can it have y and x components?

• Just to clarify, is the ladder in fact resting against a corner as JMac said. It looks that way but just want to make sure. Commented Jul 31, 2019 at 22:27
• Yes, I'll add an image so that it's clearer
– Agus
Commented Jul 31, 2019 at 22:34
• In that case I agree with (upvote) JMac's answer. Commented Jul 31, 2019 at 22:40
• You place friction in any direction and if the solution produces a negative value, then flip it. Commented Jul 31, 2019 at 23:57