This question has been previously asked, but I do not understand the answer.
When calculating the ground state energy of an interacting system by a perturbative expansion in terms of Feynman diagrams, say for the interacting electron gas, the contribution of the first-order diagrams is often referred to as the "Hartree-Fock energy" (see Nolting, just under equation 5.139, or Section 43.2 in Lancaster & Blundell).
I am conceptually familiar with the Hartree-Fock method for finding ground states of interacting systems by assuming that the quantum state can be written as a single Slater determinant, then iteratively solving for the right set of basis wavefunctions.
Am I missing some kind of deeper connection here? The answer to the linked questions seems to suggest that one can rederive the Hartree-Fock method by summing diagrams at all orders (via the self-energy), which of course involves going beyond first order. But then I don't understand why the first-order contribution is called the Hartree-Fock energy, if the connection involves going beyond first order. Is this just an unfortunate naming convention?
For context: I am interested in computing the ground state energy for a system of fermions interacting by s-wave scattering (so the pair interaction is a delta function). I computed the two first-order Feynman diagrams, and found that they cancelled out. Obviously, I know that there should be some energy change to the ground state associated with adding an interaction, so I don't see how the contributions of first-order Feynman diagrams could possibly be equivalent to Hartree-Fock.