1
$\begingroup$

The Rayleigh criterion sets the fundamental limit for what features an optical system can resolve. Formally, the criterion is defined for some wavelength $\lambda$ in the case of a uniformly-illuminated aperture (consider one that is circular) of diameter $d$. An airy disk is formed in the far field (or at the focus of a lens), with first intensity minimum described by sin($\theta_{min}$)$ = 1.22\frac{\lambda}{d}$, where $\theta_{min}$ is the angle from the optic axis to the radial location of the intensity distribution in the observation plane, from the perspective of aperture center. Two adjacent apertures can just be resolved if the peak of Airy pattern one falls over the minimum of the other. The wiki article outlines this nicely: https://en.wikipedia.org/wiki/Airy_disk.

The criterion for resolution is very general: we are only talking about an aperture thickness and wavelength. However, we can define an optimal spatial resolution too: sin($\theta_{min}$) $= x_{min}/R$, where $R$ is the distance from the aperture center to a point on the observation plane, and $x_{min}$ is a radial distance in the observation plane from the optic axis on that plane. So our fundamental resolution limit is governed by $\theta_{min}$, but we can have a varying $x_{min}$ depending on our distance to the observation plane, $R$. What then is the physical significance of $x_{min}$, if the Airy disk is the same (when plotted against $\theta$) regardless of $R$ (assuming far field)? Furthermore, when I use a lens of focal length $f$, we can say $R=f$, but how does a lens with higher optical power improve system resolution when the fundamental limit has been set in terms of the angular resolution?

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.