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Can you help me on understanding why we may say this transmission line the propagation is guided and there is not any radiation?

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It is a 2-conductors transmission line, in which the conductors are assumed to be at a very low distance. My textbook assumes that the line is open, and says that, since the currents on the wires are opposite, the EM fields cancel each other.

But, I do not understand some things:

1) How can I "see" (graphically) that tue EM fields cancel each other?

2) And if was the transmission line connected to an impedance Zl?

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