Can you help me on understanding why we may say this transmission line the propagation is guided and there is not any radiation?
It is a 2-conductors transmission line, in which the conductors are assumed to be at a very low distance. My textbook assumes that the line is open, and says that, since the currents on the wires are opposite, the EM fields cancel each other.
But, I do not understand some things:
1) How can I "see" (graphically) that tue EM fields cancel each other?
2) And if was the transmission line connected to an impedance Zl?