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This question already has an answer here:

From a recently reignited [casual] curiosity into particle physics thanks to the Fermilab YouTube channel, I read about the g-2 experiment, followed by muons, naturally. Muons, it turns out have short lives, and they decay into an electron (and antineutrino), for example. Reading on how muons are created, I learned about the role of the cosmic rays, and intuitively I understand how 3 quarks can end up as 3 quarks and a quark–antiquark pion. [Charged] pions decay to muons, so my curiosity was satisfied, but only momentarily . . .

Until I realized this muon creation and the subsequent electron originated from quarks.

Q: How are quarks elementary when they can become leptons?

I'm either misunderstanding the meaning of a particle being elementary, or I'm missing something. (I can't get my head around that point; I also casually understand that the weak interaction is involved.)

Does it work the opposite way as well (lepton → quark)? Or, given enough time, will all elementary particles eventually decay to leptons? (Thinking out loud; not necessarily extra questions.)


I could not find the answer to my question on Wikipedia or via Google. I checked the related topics, for example, Are quarks and leptons actually fundamental particles? But it's a different question about what makes up quarks/leptons (I'm content with the fact they're as small as they get according to the Standard Model).

Thanks to @AccidentalFourierTransform for the following links (and their links):

As far as I can see those posts do not address the quark → lepton decay. All the examples given are quark → another quark (or lepton → another lepton), which I have no issue with (the muon → electron example I gave). The same for the decays of virtual/mediating particles, e.g., photons and Higgs bosons. My issue is (was) the class-changing decay of the non-virtual particles.

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marked as duplicate by Jon Custer, GiorgioP, Aaron Stevens, Cosmas Zachos, ZeroTheHero Jul 20 at 1:00

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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    $\begingroup$ Quark number and lepton number are conserved. When the $\pi^+$ pion decays it produces an antimatter $\mu^+$ antimuon and a (normal matter) $\nu_\mu$ neutrino, so the lepton number remains zero (as does the quark number). $\endgroup$ – PM 2Ring Jul 9 at 4:00
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    $\begingroup$ A muon is also an elementary particle, and yet it decays into an electron and an antineutrino, as you know. Being an "elementary" particle doesn't mean it can't undergo interactions and come out as different particles, as long as quantum numbers are conserved. $\endgroup$ – Dmitry Brant Jul 9 at 4:01
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    $\begingroup$ Possible duplicate of Is the Higgs boson an elementary particle? If so, why does it decay?, Decay of elementary particle? and links therein. $\endgroup$ – AccidentalFourierTransform Jul 9 at 12:10
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Particles are called elementary if they are not made up of other particles. However, interactions can change an elementary particle into another kind of elementary particle.

Quarks and leptons are currently believed to be elementary. (This could change if we could observe particles interacting at higher energies than, say, the LHC can achieve.) However the weak interaction can, for example, turn an up quark into a down quark, and an electron into an electron neutrino. When they change, they either emit or absorb a W or Z boson, the particles that carry the weak force.

A quark can’t directly turn into a lepton, but two quarks can indirectly produce two leptons. For example, an up quark and a down antiquark can turn into a $W^+$ boson, which can then turn into a positron and an electron antineutrino.

When an elementary particle like a muon decays into other particles, it doesn’t mean that those particles were inside the muon before it decayed. It means that the muon changed into a muon neutrino, emitting a $W^-$ boson in the process, and then that $W^-$ boson changed into an electron and an electron antineutrino.

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    $\begingroup$ Shouldn't it be a $W^+$ into a positron and electron neutrino, in the third paragraph? $\endgroup$ – Lucas Baldo Jul 9 at 4:31
  • $\begingroup$ Thank you. I understand no sub-particles are involved (last sentence in the question). Also muon → electron I'm fine with (both leptons). So my misunderstanding was that quarks and leptons were their own "groups", but basically it's the concept of particles in general and the before/after spin/charge, as also commented, is all that matters, and they can jump groups, so to speak, right? $\endgroup$ – ymb1 Jul 9 at 4:31
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    $\begingroup$ Would it help the OP somehow if you said that in the example you gave, no quarks (=quark + antiquark) turn into no leptons (=electron + antineutrino)? $\endgroup$ – Martin Kochanski Jul 9 at 4:57
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    $\begingroup$ After reading this answer, it's not clear to me what "made up of other particles" means. What prevents me from thinking than a deuteron is an elementary particle that can "decay", or "change" into a proton and a neutron? This seems to be the crux of this answer, and it is not explained in detail. $\endgroup$ – Federico Poloni Jul 9 at 13:00
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    $\begingroup$ @FedericoPoloni What should prevent you from thinking that is the experimental evidence that the deuteron has internal structure. Deuteron-electron scattering reveals that there is a proton and a neutron inside a deuteron, and quarks inside each of those. So the deuteron is observed to be a complicated composite particle. A muon, by contrast, appears to have no internal structure when we scatter electrons of it. It scatters like a single point charge. $\endgroup$ – G. Smith Jul 9 at 14:22
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We have a plethora of data on particle interactions since last century, and laboriously have come up with a mathematical model for particle physics that works, i.e. it gives the right numerically answers for these data and, important, is successful in predicting new data, as recently happened with the Higgs boson. It is called the standard model for this reason and has an elementary particle table.

elem

These are what the successful model uses as elementary particles (together with their antiparticles), i.e. point particles carrying quantum numbers and masses that , when used to get the crossection of an interaction or the decay width or.. work beautifully and the model is continually validated.

In this model the elementary particles interact with the three interactions according to their quantum numbers, and some such interactions and the energy supplied by their masses allow them to decay to other elementary particles. The Z and W and the Higgs also decay into lower mass elementary particles.

So the answer is that it is a model that defines what elementary particles are which is working very well.

If in the future a string theory model, for example, can embed the standard model into vibrations of a string, there will be only one elementary entity, the string.

It is all in the model.

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    $\begingroup$ In all honesty, the OP wasn't challenging the standard model or the wisdom of the physicists who have accepted a particular set of particles as elementary based on scientific justifications (which you nicely summarize). The OP was rather trying to understand what the concept of an elementary particle is. It is natural to confuse the existence of the decay of a particle with the particle being made up of what it decays into. And I think that the question of the OP stemmed out of such a confusion. Your answer then stays orthogonal to actually addressing OP's confusion IMO. $\endgroup$ – Dvij Mankad Jul 9 at 21:40
  • $\begingroup$ @FeynmansOutforGrumpyCat Well, I have tried to say what an elementary particle is for particle physics. Having started graduate school at 1961, neutrons and protons were still considered elementary. It is the model used that defines what observations mean, imo. I have tried to state this, that what is elementary today may not be in 300 years. $\endgroup$ – anna v Jul 10 at 3:12

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