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The major factor of different scattering is the ratio of wavelength to the size of particles which are working as microscopic scattering mirrors.

In a sparse particle medium like air, the longer the wavelength, the easier it is to transmit and harder to be scattered. The shorter the wavelength, the easier it is to scatter and more difficult to transmit.

Given the size of mirrors in air, the shorter the wavelength, the stronger the scattered light, the weeker the transmitted light.

In sky, the mirrors are the air molecules. Red light gets more transmission, blue light gets more scattered.

So the sky is blue.

This is my understanding. Anything wrong with my above words, please give advise and corrections.

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closed as too broad by PM 2Ring, Qmechanic Jul 4 at 7:52

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ You forgot to ask an actual question. $\endgroup$ – PM 2Ring Jul 4 at 7:25
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    $\begingroup$ The sky is black and the Sun is white. On Earth, the atmosphere scatters the blue light in the white Sunlight so the sky looks blue - and blue light subtracted from white light is yellow light. $\endgroup$ – Cinaed Simson Jul 4 at 7:53
  • $\begingroup$ To reopen this post consider to only ask 1 subquestion per post. Watch out for duplicates. $\endgroup$ – Qmechanic Jul 4 at 7:53
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Sunsets are red because most blue light has been scattered since the light goes through more atmosphere at that angle.

https://en.wikipedia.org/wiki/Rayleigh_scattering

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