# Equilibration of a solid body with two points particles

How do I find $$\theta$$ as it $$\theta (m,d,l) and AB=L$$? And the cane which holds the two points particles(mass) is massless . In A the point mass is $$3M$$ and in B the mass is $$M$$ where there is no Friction in A and O .

I tried to apply the summary of Torques equals 0 and get $$\theta= \frac{4L}{3d}$$ but it's not correct because it should contain $$M$$ in it ... so I even tried Newton's first law and I got $$M=0$$ which is not logical .. what are the exact forces that are affecting this solid body?

• Did you consider the normal force at A? – walber97 Jul 3 '19 at 9:17
• no ... what is it – user195656 Jul 3 '19 at 9:45
• You should have to include the normal force (Force acting perpendicular to the point of contact) at A and O."A Ladder Resting Against a Wall" is a similar problem you can refer. courses.lumenlearning.com/suny-osuniversityphysics/chapter/… – walber97 Jul 3 '19 at 10:24