# Wavefunction for the deuteron's ground state

I was reading Blatt & Weisskopf's Theoretical Nuclear Physics (1979) and on the II.Two-Body Problems at Low Energies chapter, page 100, they say:

The wave function for the composite state (the ground state of the deuteron) then is: $$\phi=\phi_S + \phi_D$$

Why aren't there any normalization coefficients? Shouldn't it be a linear combinations of such states? $$\phi=a\phi_S+b\phi_D$$

• Presumably they absorb those coefficients into the normalizations of the two components. If the s and d components were individually normalized to 1, the yes, you would need the coefficients out in front. – ragnar Jul 6 at 0:12