I was reading Blatt & Weisskopf's Theoretical Nuclear Physics (1979) and on the II.Two-Body Problems at Low Energies chapter, page 100, they say:

The wave function for the composite state (the ground state of the deuteron) then is: $$\phi=\phi_S + \phi_D$$

Why aren't there any normalization coefficients? Shouldn't it be a linear combinations of such states? $$\phi=a\phi_S+b\phi_D$$

  • $\begingroup$ Presumably they absorb those coefficients into the normalizations of the two components. If the s and d components were individually normalized to 1, the yes, you would need the coefficients out in front. $\endgroup$ – ragnar Jul 6 at 0:12

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