# Can a spinning ball bounce off the floor without slipping?

Suppose a ball is dropped vertically downward, but it also given some spin along a horizontal axis. Then when the ball bounces, it will presumably pick up some horizontal velocity.

Is it possible for the ball to pick up this horizontal velocity without slipping against the ground? It would seem that, as the ball bounces, it would necessarily slip against the floor, dissipating energy. This is because the horizontal velocity of the outside edge of the ball, relative to the ground is $$\omega r$$ on impact.

We could minimize the distance the ball slips by increasing the friction coefficient. However, this increases the frictional force proportionately, so that even in the limit of infinite friction coefficient, the energy dissipated by slipping does not go to zero. Thus, it would seem that "bouncing without slipping" is not a valid description of something a ball can do.

However, some physics problems, such as problem 11 in this PDF, suggest that such a thing can happen. Where is the discrepancy?

• I don't understand the concern. Why would slipping be necessary? What about pure rolling?
– JMac
Commented Jun 26, 2019 at 17:49
• @JMac Then the ball would need to instantly pick up a horizontal velocity when contacting the floor, right? Commented Jun 26, 2019 at 18:04
• @AaronStevens If you treat the ball as free to deform you should be able to account for it without assuming it's instantly changing velocity.
– JMac
Commented Jun 26, 2019 at 18:15
• @JMac I rigidly only believe in rigid bodies :) Commented Jun 26, 2019 at 18:16
• @AaronStevens Probably not the most accurate belief in this situation :P
– JMac
Commented Jun 26, 2019 at 18:18