Can someone explain me why the Hamiltonian for the nucleon field (derived from the corresponding Lagrangian) $$H_N=\int d^3xN^\dagger(\textbf{x})\Big(-\frac{\nabla^2}{2M_0}+M_0\Big)N(\textbf{x})$$ becomes $$H_N=\sum_{i=1}^A\Big[\frac{P_i^2}{2M_0}+M_0\Big]$$ (where the sum is over the nucleons) because of baryon number conservation?


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.