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In Griffiths he mentions that a surface charge experiences a force in the presence of an electric field, but then he specifies that a force experienced by the surface is one due to its own electric field as well as other present electric fields. Why is that the case? A source charge does not experience a force from its own electric field so what is the cause or derivation of a surface charge experiencing force from its own electric field?

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    $\begingroup$ For some intuition, you can imagine the continuous surface charge to be approximated by a finite number of concentrated charges on the surface. Each of the charges exerts a force on each of the other charges, and only for special cases, would the results sum to zero. $\endgroup$ – D. Halsey Jun 16 at 13:18

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