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https://www.youtube.com/watch?v=iWKFPTgkpXo

Basically inspired by this video and its comparison with wormholes. While many other questions on the site have already covered the weak strength of gravitational waves and hence hinting the experimental feasibility, what will happen in theory when there are gravitational waves of sufficient energy to converge to a point. Do we end up with a black hole similar to how a kugleblitz works or we don't know because at the focal point, the strength of gravity will be so strong that it is no longer obeying the weak field limit and hence require a quantum gravity description?

The only thing I am certain without doing some pretty computationally intensive numerical modelling is that since gravitational waves are nonlinear, they cannot be expected to just add up in superposition, so the resulting wave may not be a spike wave.

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  • $\begingroup$ A kugleblitz doesn't work, it's a myth. Light in GR cannot be viewed as a classical electromagnetic radiation. It is a null dust with a kinetic energy that does not bend spacetime - a relativistic object (no matter one or many) with a high kinetic energy does not create a black hole. So a kugleblitz of a null dust like neutrinos or photons cannot create a black hole. This may be different for gravitational waves, if they are non-linear and not a null dust of non-interacting gravitons. $\endgroup$ – safesphere Jun 14 at 15:10
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    $\begingroup$ Most physicists do not agree with safesphere’s comment. In previous arguments he has refused to state his argument in an answer where it can be voted on because he knows it will be downvoted. A kugelblitz is mainstream physics. en.wikipedia.org/wiki/Kugelblitz_(astrophysics) $\endgroup$ – G. Smith Jun 14 at 15:23
  • $\begingroup$ @G.Smith Physics is not decided by a democratic vote or popularity contest. Referring to the majority is not a scientific argument. A collapsing sphere of ultra relativistic neutrinos does not create a black hole for the same reason as why the kinetic energy of a relativistic object does not create a black hole. The same applies to photons. Look up null dust. If you see a flaw in this logic, you are more than welcome to post, but if referring to the majority is all you got, then you don't have a logical argument. $\endgroup$ – safesphere Jun 14 at 17:15

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