Using Bernoulli's equation P Pressure p density V velocity of fluid
$$P_1+ \rho gy_1+\frac{1}{2}\rho V_1^2 = P_2+\rho gy_2+\frac{1}{2}\rho V_2^2$$ $$V_1^2-V_2^2 =\left(2g(y_2-y_1) +\frac{2(P_2-P_1)}{p}\right)$$ $$V_1^2-V_2^2 =K$$ (1) Where K is constant
Using equation of continuity $$V_1^2(\frac{ A_1}{A_2})^2 = V_2^2$$
Substitution in (1) gives $$V_1^2(1-(\frac{A_1}{A_2})^2)=K$$ Here as A1 increase V1 increase which is opposite to equation of continuity in which as A1 increase V1 decrease.
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