The standard equation of instantaneous voltage is :- $$ e = e_m \sin(\omega t) $$

In this case :- $$ e = 100 \cos(\omega t) \\ \implies e = 100 \sin(\omega t + \frac{\pi}{2}) $$

Now, $$ \omega = 2 \pi f \\ \implies f = \frac{\omega}{2 \pi} $$

If the $ \frac{\pi}{2} $ were not present, I would have easily calculated the frequency, but how can I calculate frequency in this case?


This is just a phase shift, and it can be done away with using a suitable redefinition of the origin of the time axis. For calculating the frequency it is irrelevant - you can completely disregard it.

  • $\begingroup$ After ignoring the phase shift, is there a way to calculate the frequency since the value of $ \omega $ is not given in the question ? $\endgroup$ – arandomguy Jun 9 '19 at 12:42
  • 1
    $\begingroup$ @arandomguy, not from the information you shared with us. $\endgroup$ – The Photon Jun 9 '19 at 13:55

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