After being frustrated by this figure also, I will explain my ideas thus far and hopefully others can help complete the picture or illuminate my misunderstandings.
The horizontal lines represent exchanges of states, band $r$ with $r\pm1$. For $p=5$, one expects exchanges at $4$ distinct energy levels which is the case in both figures. The large dots are electrons, and I believe the dashes and smaller dots are provided to distinguish the paths followed by different electrons.
In sub-figure (a) there are two closed orbits at the bottom of the first trough (one labelled by dots and the other by dashes). At the top of the first peak there are another two closed orbits. The remaining path labelled by dots is not closed and traverses the system exiting on the right. This single orbital travelling from left to right corresponds to the single Hall current expected from the central band.
In sub-figure (b) there are no closed orbits, there are three orbits that travel from right to left, corresponding to the negative currents and two travelling the opposite direction corresponding to the positive currents.
Some data
For the sake of completeness, I will provide some values from simple numerical calculations of $s_r$ for small $\frac{V}{V^{\prime}}$. The corresponding $t_r$, result from using the Diophantine equation: $r=qs_r + pt_r$, and $\sigma_H=\frac{e^2}{h}(t_r-t_{r-1})$, (using $e=h=1$).
For the case in sub-figure (a), with $\frac{p}{q} = 5$:
$s_1=1$, $t_1=0$, $(\sigma_H)_1=0$
$s_2=2$, $t_2=0$, $(\sigma_H)_2=0$
$s_3=-2$, $t_3=1$, $(\sigma_H)_3=1$
$s_4=-1$, $t_4=1$, $(\sigma_H)_4=0$
$s_5=0$, $t_5=1$, $(\sigma_H)_5=0$
And the case in sub-figure (b), with $\frac{p}{q} = \frac{5}{3}$:
$s_1=2$, $t_1=-1$, $(\sigma_H)_1=-1$
$s_2=-1$, $t_2=1$, $(\sigma_H)_2=2$
$s_3=1$, $t_3=0$, $(\sigma_H)_3=-1$
$s_4=-2$, $t_4=2$, $(\sigma_H)_4=2$
$s_5=0$, $t_5=1$, $(\sigma_H)_5=-1$