Setup-A charged sphere , connected to one plate of capacitor , other lead of capacitor is free.
Question-Will the capacitor plates go through a charge redistribution ?
Arguments/Counterarguments-I have tried to find answer to this question , even here on PSE , generally people insist that there will be NOTHING if I connect ONLY ONE plate of capacitor to some different potential because the charges on the unconnected plate HAVE NOWHERE TO GO.I conclude from this general answer that no charges will flow in plate and even after touching one lead of capacitor to charged sphere , nothing changes , the capacitor is as good as it would have been had it been kept on a table simply.
However I think these answers are not analysing the setup properly and are answering from the usual perspective that a capacitor is charged by a battery when it transports charges from one plate to other.
If I look at the capacitor as simply two conductors placed close to each other and one of them connected to charged sphere ,I see no point in having to COMPLETE THE CIRCUIT , the charged sphere and connected plate will simply try to reach an equipotential state along with necessary re distribution of charges on other plate (keeping it , the unconnected plate, neutral overall).
So is this good enough to conclude that YES there is a redistribution of charges ? This has troubled me alot, everyone seems to be hell bent on completing circuit , don't think it's necessary.