Suppose I have two capacitors of different capacitance $C_1$, $C_2$and they have been charged prior connecting by voltage of $V_1$ and $V_2$ respectively the positive plate of one capacitor is connected to negative plate of the other.The other plates are not connected , we thus have an incomplete loop.
Had it been a complete loop , I would have easily redistributed charges . The two plates which have been connected are at different potentials , I'm interested to know what happens next , what changes will occur in the wire and all the plates , will a change be even there or not ? If there is no change then what happens to free electrons in wire why won't they move provided the wire's end are at different potentials ?
Please help , I'm unable to think around this.
Here is what I think I going to happen , I've taken a case where capacitors are charged with 3 microcoulomb and 2 microcoulomb and then their plates are joined as shown , the system is now 3conductors - leftmost plate , the two inner plates connected taken as whole and rightmost plate and therefore charges in beginning and end on them will be same but there will be redistribution as shown in my diagram which will ensure a system of lowest energy , because obviously the two inner plates won't just stand when there are different charges on them and they are connected .
if it suites you then assume that both capacitors were identical .