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Whenever a charge say $Q_1$ and $Q_2$ is given to identical conductors we have to assume that charge is given to their outer side and not inner side to calculate redistribution.

Why? I tried to find redistribution by not following above statement and it's true that I'm not able to get right answer but i just don't why?

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marked as duplicate by John Rennie homework-and-exercises May 23 at 13:38

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Similar charges always want to get as far away from each other as possible, so they sit on the outer surface of the two conductors. Assuming both are positive it will look like this.

enter image description here

Say $Q_2$ is negative the respective charges will lie on the inner surfaces of the conductors as the two opposite charges attract each other. Like so,

enter image description here

These instances occur purely on the basics of laws of attraction and repulsion.

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  • $\begingroup$ if Q2 is negetive will the Q1 and Q2 reside on inner surface ? $\endgroup$ – Bhavay May 23 at 12:14
  • $\begingroup$ No, whatever the net sum of the two charges together (whether it's positive or negative), the net charge will sit on the outer surface. $\endgroup$ – Niamh O'SS May 23 at 12:20
  • $\begingroup$ i think u misread my question .If there is two conductors plates placed parrallel and close to each other .Now there are 4 surfaces two facing parallel and two facing away .now if q1 and q2 charge is given they it will reside on facing away surfaces as repulsion happen(and then redistribution happen).if q2 is -ve will they reside on inner(facing parallel surface ) due to attraction or still reside on facing away surfaces $\endgroup$ – Bhavay May 23 at 12:26
  • $\begingroup$ They should reside on the inner side, I will correct my answer. $\endgroup$ – Niamh O'SS May 23 at 12:47
  • $\begingroup$ can u please explain me why will.redistribution takes on inner surface in 1st case and outer surface in case 2 $\endgroup$ – Bhavay May 23 at 14:42

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