Here we have the standard set up to observe the compton effect. From what I understand, due to the particle like nature of light, when the x ray photons collide with the electrons in the scatterer they lose energy and thus have a larger wavelength.
I was just wondering that if we were to remove the scatterer and just shine a narrow beam of x ray photons on the crystal, would we still observe a compton effect. I am just wondering as even in that case, we would still have the x ray photons striking the electrons in the crystal, is the same loss of energy not present there as in the case of the photons striking the scatterer first.
One reason I think we will not observe the effect is because the electrons in the atom are tightly bound, so the photons colliding with the electrons have a very small change in their overall energy as the electrons have the effective mass of the entire atom, thus gain little energy during such a collision. Although, this is just a guess.