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Suppose I dump a certain amount of energy into a field. When does it make one particle and when does it make 2 with lower energies?

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  • $\begingroup$ The energy in what form? Presumably, you are saying you collide certain particles with certain energies. Now, I'd do you one better, how do you know which field you are "dumping energy" into? Not just how many particles are made is the question, the question is what type of particles are made as a result of the scattering. So, you don't know. You can only calculate probabilities of all different outcome states using Feynman diagrams based on the Lagrangian of your theory. $\endgroup$
    – user87745
    May 14, 2019 at 4:54

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You cannot just "dump energy" , you have to model with the interactions.

Example.

The proton proton collider distributes the energy of the scatter according to quantum mechanical formulas, to the constituents of the protons (quarks and also the sea of quarks antiquark gluon) according to specific interactions , which have a probability of being expressed, since it is the quantum mechanical framework. This process has been modeled in the Monte Carlo simulation data, and the data fitted. Where there is a bump, i.e. the monte carlo has not predicted the shape, there is a discovery, as the Higgs discovery.

higgs

The straight lines under the bump are monte carlo background according to the model with various error assumptions.

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    $\begingroup$ How about say, well a simpler example would be electron falling from higher orbit(n=3) to ground state (n=1). Does it know when to go straight from 3 to 1 and release 1 photon, and when does it go from 3 to 2 then to 1, releasing 2 photons in the process? $\endgroup$ May 12, 2019 at 9:01
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    $\begingroup$ The elementary particle interactions come with probability distributions. There is a probability for the electron to fall directly with one photon, or cascade down with more transitions. It will depend on the quantum mechanical solution for the specific atom $\endgroup$
    – anna v
    May 12, 2019 at 11:44
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The energy in what form? Presumably, you are saying you collide certain particles with certain energies. Now, I'd do you one better, how do you know which field you are "dumping energy" into? Not just how many particles are made is the question, the question is what type of particles are made as a result of the scattering. So, you don't know. You can only calculate probabilities of all different outcome states using Feynman diagrams (which are) based on the Lagrangian of your theory.


$\small\text{Of course, this is a simplified answer with a weakly coupled theory in mind which admits}$ $\small\text{(a Lagrangian and) particle states, etc. }$

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