# How can we analyze electronic capacitors in series? [closed]

Two capacitors are in series, such as in this circuit diagram:

When doing a circuit analysis, how can we describe the voltages and charges across the two capacitors?

## closed as off-topic by John Rennie, Yashas, hft, Feynmans Out for Grumpy Cat, Bill NMay 14 at 13:46

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Since there is essentially zero charge in the wire itself, and the conductor is neutral, you need the charges on the two plates to be opposite. This means that, under the most reasonable sign convention for how the capacitors are wired (i.e., with both the same way), the charges are equal: $$Q_1=Q_2.$$
This means that voltage is additive over the capacitors: $$V = V_1 + V_2.$$