1
$\begingroup$

Hi I'm stuck on a conceptual question I am working on which has frustrated me as I'm not sure I still understand this topic but essentially the question is asking:

You complete a Youngs double slit experiment and observe a good interference pattern. Out of curiosity you now use two separate light sources instead of one to illuminate the double slit. Would you observe any changes to the intereference pattern and explain why ?

I think the two light sources would have no phase relation with eachother so there would be no visible interference because they do not interfere. I don't know if this is right though and would prefer a better explanation.

Thank you for any help

Improve this question
$\endgroup$
12
  • $\begingroup$ This is basically what would happen, no interference as such $\endgroup$
    – Sidharth Giri
    May 6, 2019 at 18:10
  • $\begingroup$ There would be interference, but the phase difference between the two sources is not constant, and would be charging so fast that you won't be able to observe the pattern. $\endgroup$
    – Eagle
    May 6, 2019 at 18:15
  • $\begingroup$ I'm still confused what do you mean by charging so fast ? $\endgroup$
    – Layla
    May 6, 2019 at 18:42
  • $\begingroup$ If the two sources are separated a certain distance, you will get two superimposed interference patterns. The two slit experiment do not change in essence. $\endgroup$
    – Gluoncito
    May 6, 2019 at 18:49
  • $\begingroup$ I'm sorry but I don't understand all 3 of the answers are different to some extent im really confused ? $\endgroup$
    – Layla
    May 6, 2019 at 18:50

3 Answers 3

Reset to default
1
$\begingroup$

Look at the original geometry of Young's experiment, shown here:

enter image description here

To get a coherent source, one uses as single slit which allows only inphase waves to be transmitted, the rest are reflected back. So you would force coherence even if there were two different sources behind the first slit on the left.

Lasers have coherent beams,so the first slit can be omitted

laser

so using light from two lasers would do for your experiment. The result would be that each laser would have its own interference pattern, as seen here with blue and red lasers.

two laserdbls

It is evident if they overlap that there would be no obvious interference.

Now if you took two different lasers of the same frequency and by some clever mirror arrangements created one beam, would there be interference registered? I would say not, because of the phase differences between the two components, unless you passed the beam through the single slit as in the original Young experiment, i.e. force it to be coherent.

Improve this answer
$\endgroup$
1
  • $\begingroup$ Running the beams together first through a single slit will do nothing for the mutual temporal coherence of the two beams. There would still not be a visible fringe pattern. $\endgroup$
    – S. McGrew
    Jun 6, 2020 at 23:50
0
$\begingroup$

Recall all of your calculations for the double slit experiment. These started from assuming that the light at each slit was in phase. You now have no phase relation between the two slits, and as such none of your calculations matter. The light is out of phase and does not interfere.

Improve this answer
$\endgroup$
0
$\begingroup$

The interference will always be because the total field at a point $x$ is determined with all sources: $\square A\propto j$. Another thing is time stability of the interference picture. It really depends on time correlation of phases of different sources.

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.