Why are orbits $1.5r_{s} < r < 3r_{s}$ unstable around a Schwarzschild black hole? The "Orbital motion" section of the Wikipedia entry corresponding to Schwarzschild metric reads:

A particle orbiting in the Schwarzschild metric can have a stable circular orbit with $r > 3r_s$. Circular orbits with $r$ between $1.5r_s$ and $3r_s$ are unstable...



*

*What does justify this instability? 


Some follow-up questions:


*What would change if one consider a big object, say, a soccer ball, instead of a particle?

*Does the same result hold for rotating (Kerr) black holes?
 A: Regarding your first question:
In general relativity the energy of a light object moving around a spherically symmetric mass can be written as:
$E=mc^2(\frac{\sqrt{1-\frac{2GM}{rc^2}}}{\sqrt{1-\frac{v^2}{c^2((1-\frac{2GM}{rc^2})^2(\hat{r}\cdot\hat{v})^2+(1-\frac{2GM}{rc^2})|\hat{r}\times\hat{v}|^2)}}}) $
The strange part above is because in the Schwarzschild solution the local velocity of light is different in the radial direction and transverse to the radial direction. For pure circular motion this expression reduces to:
$E=mc^2(\frac{\sqrt{1-\frac{2GM}{rc^2}}}{\sqrt{1--\frac{v^2}{c^2(1-\frac{2GM}{rc^2})}}}) $
This can be rewritten as:
$E=mc^2(\frac{{1-\frac{2GM}{rc^2}}}{\sqrt{1-\frac{2GM}{rc^2}-\frac{v^2}{c^2}}})$
For pure stable circular motion we also have, just as classically, $v=\sqrt{GM/r}$ so we can write:
$E=mc^2(\frac{{1-\frac{2GM}{rc^2}}}{\sqrt{1-\frac{2GM}{rc^2}-\frac{GM}{rc^2}}})$
From the last expression it can be seen that infinite energy is needed to stay in a circular orbit at the photon radius $r=\frac{3GM}{c^2}=1.5r_s$. By taking the derivative of the last expression with respect to r we see that it has a minimum for $r=\frac{6GM}{c^2}$. This means that as long as you are "higher up" than $r=\frac{6GM}{c^2}=3r_s$ circular orbits require less energy to sustain as you go closer to the black hole. However, closer to the black hole than that radial distance, circular orbits require more and more energy to sustain the closer you go to the black hole, and that is why they are unstable.
