# In the ground state of helium what's the differing quantum number?

In the ground state of the helium atom, both the electrons have the same quantum numbers $$(n,l,m)$$ equal to $$(1,0,0)$$. By Pauli's exclusion principle, the fourth quantum number must be different. What is this fourth quantum number when the electrons are actually in an antisymmetric entangled spin-singlet state?

• $m_{s_1}=+1/2$ and $m_{s_2}=-1/2$? – mithusengupta123 Apr 29 at 8:33