I am taking a thermodynamics course and we have talked about stat mech and the number of possible combinations of $N$ indistinguishable particles given degeneracy $g$.
We stated that for the distinguishable case, there would be g^(N) possible configurations. Cool, that makes sense. Then to consider the case of indistinguishable particles, we just divide out by the N! equivalent arrangements. Word, totally on board... BUT the resulting form:
gives me some grief in that you can arrive at non-integer solutions. For example g = 3 , N = 2. Can anybody shed some light on the issue?