The nuclear equation for the decay of calcium-47 into scandium-47 is given by:
The following data are available: Mass of calcium-47 nucleus = 46.95455 u Mass of scandium-47 nucleus = 46.95241 u
1) Using the data, determine the max KE, in MeV, of the products in the decay of calcium-47.
2) State why the KE will be less than your value in question 1
What I don't get
1.48 MeV is what I calculated for question 1 (which is correct according to my answer book). However, why does it say in question 2 that the actual KE will be less than 1.48 MeV? The way I got to 1.48 MeV is converting the mass defect to energy, and the antineutrino (which is X in the equation) has no mass so this process of calculating 1.48 MeV doesn't take into account the KE of the antineutrino. Therefore, shouldn't the actual KE value be greater than 1.48 MeV because we are adding the antineutrino's KE to this 1.48 MeV?