From my understanding of black hole evaporation, a pair of virtual particles manages to avoid annihilating itself when one of the particles in the pair passes the event horizon and the other escapes the horizon. Wouldn't the same behavior take place at the hubble horizon? Would the hubble horizon radiation look any different from hawking radiation? The only difference between the two is that black holes shrink due to this radiation whereas the hubble horizon grows because of this radiation; both horizons "leave" us, just in different directions. Black holes emit more hawking radiation per volume as they shrink, which would look a lot like the big bang radiation from when our universe was small. Does this also imply that if you created a sphere of black hole spheres (surround a space with event horizons (or a rindler horizon)), you would create a universe?
There is thermal radiation from cosmological horizons. This is known as Gibbons–Hawking effect for their discoverers:
- Gibbons, G. W., & Hawking, S. W. (1977). Cosmological event horizons, thermodynamics, and particle creation. Physical Review D, 15(10), 2738, doi:10.1103/PhysRevD.15.2738.
Does this also imply that if you created a sphere of black hole spheres …
This would not work. For black holes $R \sim M $, so if you gather several black holes to cover a sphere they would merge and there would be simply one large black hole.