Change in area on a 3-sphere bounded by a trajectory due to a differential change in trajectory I have a 3 dimensional spherical topology, and I draw a curve onto the sphere labelled by $\vec{n}(\vec{r},t)$. The area bounded by the curve is termed the "Wess Zumino Action" (Hence my motivation to ask this site rather than math).
Now suppose I introduce an infinitesmal change to this curve, labelled $\delta \vec{n}$, then the variation in the area is given by:
\begin{equation}
\delta S = \delta \vec{n} \cdot (\vec{n} \times \partial _0 \vec{n})
\end{equation}
I tried to reason it out, but I'm not quite able to get this expression. Let's say the curve is drawn along the equator, with a small variation in the z direction. $\partial _0 \vec{n}$ should point in the direction of the curve, so $\vec{n} \times \partial _0 \vec{n}$ should give a vector that points parallel the z axis, but then the dot product doesn't really give me any intuition on why this should be the change in the area. Could someone give me a derivation, and also point toward some resources that discuss similar intuition and proofs?
I'm currently looking at Eduardo Fradkin's Condensed Matter Physics but it doesn't have more than a highly condensed treatment of topology. This is taken from eqn 7.28 and 7.42 from Eduardo Fradkin's "Field Theories of Condensed Matter physics", in the chapter titled "sigma models and topological terms"
Please let me know of any other clarifications if this isn't enough information.
 A: I don't have your reference but I think I figured it out. Just in case it isn't clear from the question, this is a 2D sphere embedded in 3D Euclidean space. $n(x^0)$ is a unit vector that traces out a closed curve on the sphere as $x^0$ is varied. We can add a coordinate and extend this to a unit vector $n(x^0,x^1)$ that will cover the entire entire area enclosed by the curve as $x^0,x^1$ are varied.
The area enclosed could be written
$$S=\int dx^0 dx^1 (\partial_0 n\times \partial_1 n)\cdot B$$
where $B$ is the magnetic field of a monopole at the center of the sphere. If it is normalized appropriately so the flux gives the area, this is just,
$$B= n.$$ The reason for calling it a `magnetic field' is we can write $B=dA$, at least in the coordinate patch covering this closed curve, so by Stoke's theorem we can instead write,
$$S=\int dx^0 A\cdot \partial_0 n$$
Note that $A$ varies on the sphere so it is a function of $n$. For what comes next I will use index notation and Latin indices refer to the Euclidean space $n$ lives in, not the $x^0,x^1$ coordinates.
$$\delta S = \int dx^0 \left(\delta A^a\partial_0 n^a-\partial_0A^a\delta n^a\right)=\int dx^0 \left(\partial_b A^a \delta n^b\partial_0 n^a-\partial_bA^a \partial_0 n^b\delta n^a\right)=\int dx^0 \delta n^a\left(\partial_a A^b -\partial_b A^a \right)\partial_0 n^b$$
Now what's in the paranthesis is just the curl of $A$, which is $B=n$. Specifically, in terms of indices it is $\epsilon_{abc}n^c$ (where $\epsilon$ is the Levi-Civita symbol).
So going back to vector notation I have
$$\delta S = \int dx^0 \delta n\cdot \left(\partial_0 n \times n\right)$$
