enter image description here

Fluid of density $\rho$ is flowing through a pipe with area $A$ with velocity of $V$. The pipe divides into two different pipes of area $\frac{1}{2}A$ and $\frac{3}{2}A$ with the right end opened. All the pipes are at the same height. How do I represent the velocity of fluid at each paths?

I tried using Bernoulli's equation and continuity equation and got the following results: $ p_0+\frac{1}{2}\rho V^2 = p_1+\frac{1}{2}\rho V_1^2 = p_2+\frac{1}{2}\rho V_2^2 $, $V_1 + 3V_2 = 2V$.

However, I can't find any more equations from here. Also, I'm stuck at the second question too, where the two pipes are separated by height $H$ and have the same area $A$.

enter image description here

Thank you in advance.


closed as off-topic by Kyle Kanos, Gert, GiorgioP, John Rennie, ZeroTheHero Apr 16 at 13:39

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "Homework-like questions should ask about a specific physics concept and show some effort to work through the problem. We want our questions to be useful to the broader community, and to future users. See our meta site for more guidance on how to edit your question to make it better" – Kyle Kanos, Gert, GiorgioP, John Rennie, ZeroTheHero
If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ Add equations: in the first case $p_1=p_2$, in the second case $p_1=p_2+\rho gH$ $\endgroup$ – Alex Trounev Apr 15 at 14:08
  • $\begingroup$ @AlexTrounev How do you know that $p_1 = p_2$? $\endgroup$ – Dimen Apr 16 at 2:51
  • $\begingroup$ Are the outlets of the pipe discharging into atmosphere (or some other common reservoir)? $\endgroup$ – Deep Apr 16 at 4:44