You are given an p(V) - Diagram like this:
There you see two isothermal processes and two isochor processes. For every given isothermial process I can exactly calculate the heat supplied by:
$\Delta U = \Delta W + \Delta Q = 0 \implies \int p(V)dV=- \Delta Q$
Now I assume an isobar process (not seen in the Diagram): Again I know:
$\Delta U = \Delta W + \Delta Q \implies \int p(V)dV= \Delta U - \Delta Q$
But can I make a more precise statment? Can I calculate the heat supplied? Same for isochor processes, where:
$\Delta U = \Delta Q$
I am wondering because I suppose that given this diagram (the circle), there should be an equilibrium of Energy supplied and Energy absorbed...